Optimal. Leaf size=167 \[ -\frac{2 c (d+e x)^{m+1} \, _2F_1\left (1,m+1;m+2;\frac{2 c (d+e x)}{2 c d-\left (b-\sqrt{b^2-4 a c}\right ) e}\right )}{(m+1) \left (2 c d-e \left (b-\sqrt{b^2-4 a c}\right )\right )}-\frac{2 c (d+e x)^{m+1} \, _2F_1\left (1,m+1;m+2;\frac{2 c (d+e x)}{2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e}\right )}{(m+1) \left (2 c d-e \left (\sqrt{b^2-4 a c}+b\right )\right )} \]
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Rubi [A] time = 0.299823, antiderivative size = 167, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 2, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.077, Rules used = {830, 68} \[ -\frac{2 c (d+e x)^{m+1} \, _2F_1\left (1,m+1;m+2;\frac{2 c (d+e x)}{2 c d-\left (b-\sqrt{b^2-4 a c}\right ) e}\right )}{(m+1) \left (2 c d-e \left (b-\sqrt{b^2-4 a c}\right )\right )}-\frac{2 c (d+e x)^{m+1} \, _2F_1\left (1,m+1;m+2;\frac{2 c (d+e x)}{2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e}\right )}{(m+1) \left (2 c d-e \left (\sqrt{b^2-4 a c}+b\right )\right )} \]
Antiderivative was successfully verified.
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Rule 830
Rule 68
Rubi steps
\begin{align*} \int \frac{(b+2 c x) (d+e x)^m}{a+b x+c x^2} \, dx &=\int \left (\frac{2 c (d+e x)^m}{b-\sqrt{b^2-4 a c}+2 c x}+\frac{2 c (d+e x)^m}{b+\sqrt{b^2-4 a c}+2 c x}\right ) \, dx\\ &=(2 c) \int \frac{(d+e x)^m}{b-\sqrt{b^2-4 a c}+2 c x} \, dx+(2 c) \int \frac{(d+e x)^m}{b+\sqrt{b^2-4 a c}+2 c x} \, dx\\ &=-\frac{2 c (d+e x)^{1+m} \, _2F_1\left (1,1+m;2+m;\frac{2 c (d+e x)}{2 c d-\left (b-\sqrt{b^2-4 a c}\right ) e}\right )}{\left (2 c d-\left (b-\sqrt{b^2-4 a c}\right ) e\right ) (1+m)}-\frac{2 c (d+e x)^{1+m} \, _2F_1\left (1,1+m;2+m;\frac{2 c (d+e x)}{2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e}\right )}{\left (2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e\right ) (1+m)}\\ \end{align*}
Mathematica [A] time = 0.256069, size = 152, normalized size = 0.91 \[ \frac{2 c (d+e x)^{m+1} \left (-\frac{\, _2F_1\left (1,m+1;m+2;\frac{2 c (d+e x)}{2 c d+\left (\sqrt{b^2-4 a c}-b\right ) e}\right )}{e \left (\sqrt{b^2-4 a c}-b\right )+2 c d}-\frac{\, _2F_1\left (1,m+1;m+2;\frac{2 c (d+e x)}{2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e}\right )}{2 c d-e \left (\sqrt{b^2-4 a c}+b\right )}\right )}{m+1} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.096, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( 2\,cx+b \right ) \left ( ex+d \right ) ^{m}}{c{x}^{2}+bx+a}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (2 \, c x + b\right )}{\left (e x + d\right )}^{m}}{c x^{2} + b x + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (2 \, c x + b\right )}{\left (e x + d\right )}^{m}}{c x^{2} + b x + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (b + 2 c x\right ) \left (d + e x\right )^{m}}{a + b x + c x^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (2 \, c x + b\right )}{\left (e x + d\right )}^{m}}{c x^{2} + b x + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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